MATH SOLVE

2 months ago

Q:
# Which expression is equivalent to square root 55x^7 y^6/11x^11 y^8? Assume x > 0 and y > 0.

Accepted Solution

A:

The first step for solving this expression is to reduce the fraction with 11.

[tex] \sqrt{ \frac{5 x^{7} y^{6} }{ x^{11} y^{8} } } [/tex]

Now reduce the fraction with [tex] x^{7} [/tex].

[tex] \sqrt{ \frac{5 y^{6} }{ x^{4} y^{8} } } [/tex]

Reduce the fraction one more time with [tex] y^{6} [/tex].

[tex] \sqrt{ \frac{5}{ x^{4} y^{2} } } [/tex]

To take the root of a fraction,, we must take the root of the numerator and denominator separately. This rule will change the expression to the following:

[tex] \frac{ \sqrt{5} }{ x^{2} y} [/tex]

Since we cannot simplify this fraction any further,, the final answer is going to be [tex] \frac{ \sqrt{5} }{ x^{2} y} [/tex].

Let me know if you have any further questions.

:)

[tex] \sqrt{ \frac{5 x^{7} y^{6} }{ x^{11} y^{8} } } [/tex]

Now reduce the fraction with [tex] x^{7} [/tex].

[tex] \sqrt{ \frac{5 y^{6} }{ x^{4} y^{8} } } [/tex]

Reduce the fraction one more time with [tex] y^{6} [/tex].

[tex] \sqrt{ \frac{5}{ x^{4} y^{2} } } [/tex]

To take the root of a fraction,, we must take the root of the numerator and denominator separately. This rule will change the expression to the following:

[tex] \frac{ \sqrt{5} }{ x^{2} y} [/tex]

Since we cannot simplify this fraction any further,, the final answer is going to be [tex] \frac{ \sqrt{5} }{ x^{2} y} [/tex].

Let me know if you have any further questions.

:)