MATH SOLVE

4 months ago

Q:
# a rectangle has a length of x inches and a width 3 inches less than the length. if the dimensions were doubled , what would be the area of the new rectangle in terms of x ?

Accepted Solution

A:

original length: x

original width; x-3

original area: x(x-3)

when the dimensions doubles, that is, increase by a factor of 2, the area increase by 2²

4[x(x-3)]

4x(x-3)=4x²-12x

you can also do it this way:

original length: x doubled: 2x

original width; x-3 doubled: 2(x-3)

new area: 2x[2(x-3)]= 4x²-12x

original width; x-3

original area: x(x-3)

when the dimensions doubles, that is, increase by a factor of 2, the area increase by 2²

4[x(x-3)]

4x(x-3)=4x²-12x

you can also do it this way:

original length: x doubled: 2x

original width; x-3 doubled: 2(x-3)

new area: 2x[2(x-3)]= 4x²-12x